Answer:
a) [tex]\boxed{\boxed{\sf p = 18 }}[/tex]
b) [tex]\boxed{\boxed{\sf t = 3 }}[/tex]
c) [tex]\boxed{\boxed{\sf p = 6 / by /5 }}[/tex]
Explanation -
a) 2/3 p + 10 = r
Value of r = 22 (given)
2/3 p + 10 = 22
2/3 p = 22- 10
2/3 p = 12
p = 12 × 3 /2
p = 6 × 3
p=18
b) (-17) + 5k = t
value of k = 4 (given)
(-17) +5 (4) = t
(-17) + 20 = t
3 = t
c) 0 = 5p - 3b
b= 2 (given)
0 = 5p - 3(2)
0 = 5p - 6
6 = 5p
6/5 = p
