Answer:
f(3x + 4) = 5x + 8
⇔ f(3x + 4) = [tex]\frac{5}{3}(3x+\frac{24}{5})[/tex]
⇔ f(3x + 4) = [tex]\frac{5}{3}(3x+4+\frac{4}{5})[/tex]
⇒ f'(x) = [tex]\frac{5}{3}(x+\frac{4}{5})[/tex]
=> f(3) = [tex]\frac{5}{3}(3+\frac{4}{5})= \frac{19}{3}[/tex]
Step-by-step explanation:
