Answer:
The answer is "14".
Explanation:
Let the IP address [tex]= 196.45.204.0[/tex]
When it borrowed 4 bits
[tex]\therefore\\\\ subnet = 28[/tex]
[tex]IP= \frac{196.45.204.0}{28}\\\\ 28 \to 11111111.11111111.11111111.11110000[/tex]
If the borrowed bits are left out then:
The Number of useable host addresses:
[tex]= {(2^4) - 2} \\\\ = 16-2\\\\ =14[/tex]
