Answer:
[tex]y=24,[/tex] when [tex]x=1[/tex].
Step-by-step explanation:
Given: [tex]y=4x+20[/tex]
To find: Value of [tex]y[/tex], substituting the known value of [tex]x[/tex]
We have,
[tex]y=4x+20 ...(i)[/tex]
Putting [tex]x=1[/tex] in equation [tex](i)[/tex], we get
[tex]y=4(1)+20[/tex]
[tex]\implies y=4+20[/tex]
[tex]\implies y=24[/tex]
Hence, the value of [tex]y[/tex] is [tex]24[/tex], when the value of [tex]x[/tex] is [tex]1[/tex].
