Respuesta :

raduoprea160

Answer:

x∈(20/3;26/3)

Step-by-step explanation:

12 < 2x-4/3 < 16

first we add 4/3 to each side

12+4/3<2x<16+4/3

we bring to the same denominator

12*3/3+4/3<2x<16*3/3+4/3

(36+4)/3<2x<(48+4/3)

40/3<2x<52/3

now we divide by 2

20/3<x<26/3

x∈(20/3;26/3)

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