Answer:
Well I got 9 log 10 (2)/ 3-3log10 (5)
Please correct me if I am wrong
Step-by-step explanation:
You have to apply the rule alogc (b) (b^a)
= [tex]\frac{log10(\sqrt{8))^{4}-log10((\frac{1}{2}))^{3}) } }{3-6log10(\sqrt{5}) }[/tex]
\frac{\log _{10}\left(\frac{\left(\sqrt{8}\right)^4}{\left(\frac{1}{2}\right)^3}\right)}{3-6\log _{10}\left(\sqrt{5}\right)}
