Number of Silver atoms : N = 7.8 x 10²² atoms
Further explanation
Given
mass of bracelet : 13.94 g
Required
Number of atoms
Solution
Assuming the bracelet consists entirely of silver
mol of silver :
= mass : molar mass
= 13.94 g : 107,8682 g/mol
= 0.129
Number of atoms :
N = n x No(No = Avogadro's number)
N = 0.129 x 6.02 x 10²³
N = 7.8 x 10²² atoms
