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09-02-2021
Chemistry

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How many molecules are present in 0.93 grams of Fe2O3?

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Аноним Аноним

09-02-2021

Answer:

5.8125*10^-3

the moles in Fe2O3 are 0.93/(56*2 + 16*3) = 5.8125*10^-3

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