Answer:
0.00446
Step-by-step explanation:
We need to find the value of the following expression :
[tex]\dfrac{(\dfrac{95}{17})^{-3}}{(\dfrac{15}{17})^{-2}}[/tex]
We know that, [tex]\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}[/tex]
So,
[tex]\dfrac{(\dfrac{95}{17})^{-3}}{(\dfrac{15}{17})^{-2}}=(\dfrac{95}{17})^{-3}\times (\dfrac{17}{15})^2\\\\=0.00446[/tex]
So, the value of the given expression is 0.00446.
