krystalcaudle
krystalcaudle
07-11-2016
Mathematics
contestada
I need to factor 4n^2+4n-3. How??
Respuesta :
Аноним
Аноним
07-11-2016
Simple.....
you have: [tex] 4n^{2} +4n-3[/tex]
What multiplies to -12 and adds to 4?
6*-2=-12
6+-2=4
If you plug it into the box method you should get...--->>>
(2n-1)(2n+3)
Thus, your answer.
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