mahasimahmed55 mahasimahmed55

06-03-2021
Physics

contestada

8) A force of 10 N stretches a spring 0.50 m from equilibrium. What is the value of the spring constant?

Respuesta :

coolwow789 coolwow789

06-03-2021

Explanation:

We use Hooke's Law, which states that,

F=kx

F- is the force in newtons

k- is the spring constant

x- is the extension of the spring in meters

Solving for k we get k=F/x

k= 10N/0.50m

=100 N/m

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