jesusserrato351 jesusserrato351
  • 06-03-2021
  • Mathematics
contestada

Need help!!........................................

Need help class=

Respuesta :

akposevictor
akposevictor akposevictor
  • 11-03-2021

Answer:

C. [tex] \sqrt{48} [/tex]

Step-by-step explanation:

Applying the leg rule which is given as:

Hypotenuse/leg = leg/part

Hypotenuse = 8 cm

Leg = z

Part = 6 cm

Plug in the values

[tex] \frac{8}{z} = \frac{z}{6} [/tex]

Cross multiply

[tex] z*z = 8*6 [/tex]

[tex] z^2 = 48 [/tex]

[tex] \sqrt{z^2} = \sqrt{48} [/tex]

[tex] z = \sqrt{48} [/tex]

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