Answer:
The answer is C
[tex]3 {w}^{2} + 10w + 8[/tex]
Step-by-step explanation:
Let The width as (w) and lenth as(l)
Then l=3w
When the width increase by 2
Then the New width is w+2
And the lenth increase by 4
Then the New lenth is 3w+4
Then we can find the area
[tex](w + 2)(3w + 4) \\ 3 {w}^{2} + 10w + 8[/tex]
