Answer:
A. 0.48mol O2
Explanation:
The balanced equation is given as follows:
2CH3OH + 3O2 → 2CO2 + 4H2O
This shows that 2moles of CH3OH is required to react with 3 moles of O2
If 0.32 moles of CH3OH are reacted, then;
0.32 × 3/2 moles of O2 is required
= 0.96/2
= 0.48mol of O2
