vondasiap123 vondasiap123
  • 08-04-2021
  • Chemistry
contestada

how many moles of sodium phosphate are required to make 7.5 moles of sodium nitrate in 2Na3PO4+3Be(NO3)=6NanO3+Be3(PO4)2

Respuesta :

nikitaakishev2809 nikitaakishev2809
  • 08-04-2021

Answer:

2.5 moles of sodium phosphate

Explanation:

3 Pb(NO3)2 + 2 Na3PO4 → Pb3(PO4)2 + 6 NaNO3

6 (moles in the reaction)- 7.5(moles  in the task)

2 (moles in the reaction)- x (moles in answer) ⇒6x = 2*7.5 ⇒ x = 15/6=2.5 (moles)

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