Answer: Yes
Step-by-step explanation:
Given
Dimension of the toolbox is [tex]10\ in.\times 4\ in.\times 3\ in.[/tex]
suppose the length of the box is doubled, then a new length will be [tex]2\times 10\ in.[/tex]
So, the volume of the box becomes
[tex]\Rightarrow V=2\times 10\times 4\times 3[/tex]
It can also be written as
[tex]\Rightarrow V=2\times (10\times 4\times 3)=2\times (V_{old})[/tex]
i.e. the volume of the toolbox is doubled. Therefore, Andrea is correct.
