Answer:
D. 29°
Step-by-step explanation:
Triangle ACB is an isosceles triangle so the two base angles are the same(61° and 61°). A triangle's angles must add up to 180, so take 180-61-61.
180-61-61 = 58
Divide by 2 to find angle ACB:
58/2 = 29
Option D; 29°
ΔAOB is isosceles triangle: so ∠B = ∠A, ∠A = 61, therefore:
∠O = 180 - (61 + 61)
∠O = 58
and ∠C = 58 / 2
∠C = 29
Hope this helps!
