Answer:
[tex]x^2+y^2+14y+36=0[/tex]
Step-by-step explanation:
Given that,
Center = (2,-9)
Radius of the circle, r = 7
We need to find the equation of a circle with a center at (2, -9) and a radius of 7. It can be given by :
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Put h = 2, k = -9 and r = 7 So,
[tex](x-2)^2+(y-(-9))^2=7^2\\\\x^2+4-4x+y^2+81+18y=49\\\\x^2+y^2+14y+85-49=0\\\\x^2+y^2+14y+36=0[/tex]
Hence, this is the required solution.
