Answer:
58 units²
Step-by-step explanation:
Using Pythagoras identity
The square on the hypotenuse ( third side ) is equal to the sum of the squares on the other 2 sides, then
area = 7² + 3² = 49 + 9 = 58
Firstly: using pythagoras theorem
Hyp^2=adj^2+opp^2
Let the hyp be x
X^2=7^2+3^2
X^2=49+9
X^2=58
X=Square root 58
Let the side is root 58
Area of a square is L^2
Root 58×root 58
The area of the square is 58unit squ
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