Answer:
[tex] \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2} [/tex]
Answer C is correct
Step-by-step explanation:
[tex] \sqrt[3]{ \frac{ {x}^{2} }{8 {y}^{ - 1} } } \\ \frac{ {x}^{2 \times \frac{1}{3} } \times {y}^{1 \times \frac{1}{3} } }{ \sqrt[3]{8} } \\ = \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2} [/tex]
