Answer:
[tex]\text{A. The zeroes are 8 and -4, because }y=(x-8)(x+4)[/tex]
Step-by-step explanation:
[tex]x^2-4x-32=0,\\(x-8)(x+4)=0,\\\begin{cases}x-8=0, x=\boxed{8},\\x+4=0, x=\boxed{-4}\end{cases}[/tex]
