Answer:
Step-by-step explanation:
16c^4p^2 + 20cp^3
take common
=4cp^2(4c^3 + 5p)
Given the expression below:
[tex] \large \boxed{16 {c}^{4} {p}^{2} + 20c {p}^{3} }[/tex]
We can factor out c-term, p² and 4 (from 16 and 20)
[tex] \large{4c {p}^{2} (4 {c}^{3} + 5p)}[/tex]
Answer
