eli8zbertosym eli8zbertosym

09-12-2016
Chemistry

contestada

What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

Respuesta :

syed514 syed514

09-12-2016

First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2

Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2

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23simpsona 23simpsona

03-02-2021

the answer is c) 11.2 L

edge 2021

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