Step-by-step explanation:
The distance between the point anywhere in the circumference of the circle and the centre of the circle is 2,
[tex] \sqrt{(1 - x {)}^{2} + {(3 - y)}^{2} } = 2 \\ 1 - 2x + {x}^{2} + 9 - 6y + {y}^{2} = 2 \\ [/tex]
Therefore the equation of circle is:
[tex] {x}^{2} + {y}^{2} - 2x - 6y + 8 = 0[/tex]
