Allishenie1230 Allishenie1230

06-07-2021
Mathematics

contestada

Can someone please help me by putting me where each one goes? !!

Can someone please help me by putting me where each one goes class=

Respuesta :

sankari2912 sankari2912

07-07-2021

Answer:

5(x-2) = 5x -7

- no solution

-3(x-4) = 3x + 12

- infinitely many solution

4(x+1) = 3x + 4

- Only one solution

-2(x-3) = 2x -6

- Only one solution

6(x+5) = 6x + 11

- no solution

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