Answer:
[tex]9p^2-16q^2[/tex]
[tex](3p)^{2} -(4p)^{2}[/tex]
[tex]\underline{x^2-y^2=\left(x+y\right)\left(x-y\right)}[/tex]
[tex]\left(3p\right)^2-\left(4q\right)^2=\left(3p+4q\right)\left(3p-4q\right)[/tex]
[tex]=\left(3p+4q\right)\left(3p-4q\right)[/tex]
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hope it helps....
have a great day!!
