williamszhane8562 williamszhane8562
  • 08-07-2021
  • Mathematics
contestada

Aflati al 2013 lea termen al unei progresii aritmetice cu termenul al treilea egal cu 12 si diferenta a doi termeni consecutivi, 4.

Respuesta :

fichoh
fichoh fichoh
  • 09-07-2021

Răspuns:

8052

Explicație pas cu pas:

Al treilea termen al unei progresii aritmetice:

T (n) = a + (n - 1) d

Unde ;

a = primul termen; d = diferență comună = 4; n = al treilea termen (numărul termenului)

Al treilea (3) termen:

T (3) = a + (3-1) 4

T (3) = 12

12 = a + 2 (4)

12 = a + 8

12 - 8 = a

4 = a

Prin urmare, primul termen = a

Al 2013-lea mandat;

T (2013) = a + (2013-1) d

T (2013) = 4 + (2012) 4

T (2013) = 4 + 8048

= 8052

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