Respuesta :

hufederico984
I’m not sure if I’m right

c(1)=c
cx1=c

c(n)=c(n-1)=c=0, n€R

cn=cx(n-1)

nc=cx(n-1)

nc=nc-c

0=-c

-c=0

c=0

c=0, n€R
hope this helps
C(1)=c the absolute value of any number is always positive and any expression multiple by 1 remains the same c(n) = (n-1) c=0. Hopes that helps

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