chaarmid chaarmid
  • 07-08-2021
  • Mathematics
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Helppppp me plss, I’ll mark u as brainlest

Helppppp me plss Ill mark u as brainlest class=

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ItzImran01
ItzImran01 ItzImran01
  • 07-08-2021

[tex] \large\color{lime}\boxed{\colorbox{black}{Answer : - }}[/tex]

We know that, in ∆ABC,

∠A+∠B+∠C = 180°

But the triangle is right angled at C

ie., ∠C = 90°

Therefore, ∠A+∠B+ 90° = 180°

⇒ ∠A + ∠B = 90°

Therefore, cos(A + B) = cos 90º = 0

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