Respuesta :

Novachrono12

Answer:

[H⁺] = [tex]6.3096[/tex]×[tex]10^{-4}[/tex] M

Explanation:

pH= - log[H⁺]

=> 3.2 = - log[H⁺]

=> [H⁺] = [tex]10^{-3.2}[/tex]

∴ [H⁺] = [tex]6.3096[/tex]×[tex]10^{-4}[/tex] M

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