harrisoncam700
harrisoncam700 harrisoncam700
  • 06-09-2021
  • Mathematics
contestada

For f(x)=4x+1 and g(x)=x^2-5 find (fg)(x)

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 06-09-2021

Answer:

4x^3+x^2-20x-5

Step-by-step explanation:

f(x)=4x+1 and g(x)=x^2-5

(fg)(x) = f(x) *g(x)

         = (4x+1) *(x^2-5)

FOILing

First 4x*x^2 = 4x^3

outer 4x*-5 = -20x

inner 1 * x^2 = x^2

last 1 * -5 = -5

Add them together

         = 4x^3 -20x+x^2-5

Put the terms in order from greatest power to least power

         =4x^3+x^2-20x-5

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