fuentesanthony032905 fuentesanthony032905
  • 06-10-2021
  • Mathematics
contestada

For any nonnegative real number.

For any nonnegative real number class=

Respuesta :

danielgeyfman
danielgeyfman danielgeyfman
  • 06-10-2021

Answer:

A

Step-by-step explanation:

We know that [tex]\sqrt{b}=b^{1/2}[/tex].

We also know that [tex](a^b)^c=a^{bc}[/tex].

We can combine these facts to get [tex](\sqrt{b})^2=(b^{1/2})^2=b^{1/2*2}=b^{1}=b[/tex].

So, the answer is [tex]\boxed{A}[/tex] and we're done!

Note: the non-negative part or the equation comes from the fact that you assume the square root of a negative number doesn't exist. You will change this assumption later in the year, or in further years.

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