Answer: Let the 2 numbers be x and
sum of two numbers is 28....Eq 1: x + y = 28
sum of 6 times the 1st number and 3 times the 2nd number is 105....Eq 2: 6x + 3y = 105
Rearrange Eq 1 to solve for x.
x + y = 28
x = 28 - y --> Substitute into Eq 2, you get
6(28 - y) + 3y = 105
168 - 6y + 3y = 105
-3y = -63
y = -63 / -3 = 21
Now solve for x using Eq 1.
x = 28 - y = 28 - 21 = 7
hope it helped
Step-by-step explanation:
