tay30914
tay30914 tay30914
  • 09-10-2021
  • Mathematics
contestada

​​someone pls help meeeee!!!!!!
​​

someone pls help meeeee class=

Respuesta :

ItzMeÆXO
ItzMeÆXO ItzMeÆXO
  • 09-10-2021

Step-by-step explanation:

y = y

x - 2 = 2x - 3 - 3x²

3x² + x - 2x = - 3 + 2

3x² - x = - 1

.

a = 3, b = -1, c = 0

.

[tex]\sf{x = \frac{-b \pm \sqrt{b^{2} - 4ac} }{2a} }[/tex]

[tex]\sf{x = \frac{- (-1) \pm \sqrt{-1^{2} - 4 (0)} }{2(3)} }[/tex]

[tex]\sf{x = \frac{ 1 \pm \sqrt{1 - 0} }{6} }[/tex]

[tex]\sf{x = \frac{ 1 \pm \sqrt{1} }{6} }[/tex]

[tex]\sf{x = \frac{ 1 + 1 }{6} }[/tex]

[tex]\sf{x = \frac{ 2 }{6} }[/tex]

[tex]\sf{x = \frac{ 1 }{3} }[/tex]

.

Substitution :

y = x - 2

y = ⅓ - 2

y = ⅓ - 6/3

y = - 5/3

y = - 1 ⅔

.

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