[tex] {x}^{2} + 4x - 4 = 8 \\ = > {x}^{2} + 4x - 4 - 8 = 0 \\ = > {x}^{2} + 4x - 12 = 0 \\ = > {x}^{2} + 6x - 2x - 12 = 0 \\ = > x(x + 6) - 2(x + 6) = 0 \\ = > (x - 2)(x + 6) = 0 \\ = > x = 2 \: \: \: or \: \: \: x = - 6 [/tex]
Answer:
x = -6 or x = 2
Hope you could get an idea from here.
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