Answer:
6 units
Step-by-step explanation:
use the distance formula to find the new length of JK, which is J'K'
d = [tex]\sqrt{(y-y)^2+(x-x)^2}[/tex]
coordinates of J: (-7,3)
coordinates of J': (-7/2, 3/2)
coordinates of K: (3/2, -3/2)
d = [tex]\sqrt{(-3/2-3/2)^2+(3/2-(-3/2)^2}[/tex]
d = [tex]\sqrt{(-6/2)^2+(-10/2)^2}[/tex]
d = [tex]\sqrt{3^2+5^2}[/tex]
d = [tex]\sqrt{36}[/tex]
d = 6
