Respuesta :

[tex]\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8\\ a=15.7\\ b=6.6 \end{cases}\implies A=\cfrac{8(15.7+6.6)}{2}\implies A=89.2~in^2[/tex]
A = 89.2


Hope it’s right sorry if it isn’t.

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