Answer:
[tex]x(x−3)+2=x.x−3x+2 \\ =x2−3x+2 \\F or x=1 \\ putting \: x=1 \: in \: expression \\ x2−3x+2=(1)2−3(1)+2 \\ =1−3+2 \\ =3−3 \\ =0[/tex]
[tex]Solve \: 3y(2y−7)−3(y−4)−63 for y=−2 \\ First \: simplify \: it, \\ =6y2−21y−3y+12−63 \\ =6y2−24y−51 \\ Put \: y=−2 \: =6(−2)2−24(−2)−51 \\ =6×4+48−51 \: 6×4+48−51 \\ 24+48−51 \\ =21[/tex]
