keeneyatt keeneyatt
  • 09-01-2022
  • Mathematics
contestada

6b+bx=ax+a2 solve for x

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jdoe0001 jdoe0001
  • 10-01-2022

[tex]6b+bx=ax+a^2\implies 60-a^2+bx=ax\implies 60-a^2=ax-bx \\\\\\ \stackrel{\underset{\qquad \downarrow }{\textit{common factoring}}}{60-a^2=x(a-b)}\implies \cfrac{60-a^2}{a-b}=x[/tex]

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mohadxmox mohadxmox
  • 10-01-2022

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x
=
a
2
−
6
b
b
−
a
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