Answer:
(a) CG·CE = CH·CD
(b) DH = 3 in
Step-by-step explanation:
a)
From the common point, the product of distances to the near and far intersections with the circle is the same for both secants:
CG·CE = CH·CD
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b)
It is possible to find HD given the information.
(4 in)(4 in +6 in) = (5 in)(5 in + DH) . . . . . . fill in the given values
40 in² = 25 in² +(5 in)(DH) . . . . simplify
15 in² = (5 in)(DH) . . . . . . . subtract 25 in²
3 in = DH . . . . . . . . . . . divide by 5 in
