Answer:
1) x = -5 or 9; 2) x =7 or 0
Step-by-step explanation:
1) [tex]\frac{a}{b} = \frac{c}{d}; ad = bc[/tex]
So just multiply to get
[tex]8x + 48 = x^2 + 4x + 3\\0 = x^2 - 4x - 45\\(x + 5)(x - 9) = 0[/tex]
2) Multiply by the LCM, in this case it is 2x - 6 as (x-3)(2) = 2x -6.
You get:
[tex](2)(x)+(x)\left(x-3\right)=6x\\2x + x^2 -3x -6x = 0\\x^2 - 7x = 0\\take\ out\ the\ x\\x(x-7) = 0\\x = 0 \ or \ x = 7[/tex]
