Answer:
b = 0
b = 4
Step-by-step explanation:
[tex] \frac{5}{ {3b}^{3} - {2b}^{2} - 5 } = \frac{2}{ {b}^{3} - 2 } \\ 5( {b}^{3} - 2) = 2( {3b}^{3} - {2b}^{2} - 5) \\ {5b}^{3} - 10 = {6b}^{3} - {4b}^{2} - 10 \\ 10 - 10 = {6b}^{3} - {5b}^{3} - {4b}^{2} \\ 0 = {b}^{3} - {4b}^{2} \\ 0 = {b}^{2} (b - 4) \\ [/tex]
b = 0 or b - 4 = 0
b = 0
b = 4
