The precision (relative error) of the centripetal force is 1%.
Relative error
This is the error in measurement of a variable obtained in comparison with other variables.
F = mv²/r
where;
- F is centripetal force
- m is mass
- v is velocity
- r is radius
F/m = v²/r
F/m = (0.01v)²/(0.01r)
F/m = 0.01v²/r
F/m = 1%(v²/r)
Thus, the precision (relative error) of the centripetal force is 1%.
Learn more about relative error here: https://brainly.com/question/13370015
