Answer:
1. Label Each Compound With a Variable
aLi3N + bNH4NO3 = cLiNO3 + d(NH4)3N
2. Create a System of Equations, One Per Element
Li: 3a + 0b = 1c + 0d
N: 1a + 2b = 1c + 4d
H: 0a + 4b = 0c + 12d
O: 0a + 3b = 3c + 0d
3. Solve For All Variables (using substitution, gauss elimination, or a calculator)
a = 1
b = 3
c = 3
d = 1
Explanation:
