jackthomasdudley
jackthomasdudley jackthomasdudley
  • 10-03-2022
  • Chemistry
contestada

At what temperature will 0.371 moles of neon gas occupy 10.30L at 2.50 atm?

Respuesta :

Counterfitest Counterfitest
  • 10-03-2022

Answer:

T=846K

Explanation:

We can use the formula for the Ideal Gas Equation, which is

[tex]PV=nRT[/tex]

P=pressure

V=volume

n=mols of gas

R=constant (0.08201 L-atm/mol-K)

T=temperature

We will have to rearrange to equation to find temperature, which is

[tex]T=\frac{PV}{nR}[/tex]

Time to solve:

[tex]T=\frac{(2.50 atm)(10.30L)}{(0.371 mols)(0.08206 L-atm/mol-K)}[/tex]

[tex]T=846 K[/tex]

If you want to convert to Celsius, subtract 273 to your answer, which will get you 573ºC.

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