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10-03-2022
Mathematics

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Suppose that x = x(t) and y = y(t) are both functions of t. If x^2 + y^2 = 25, and dx/dt = 2 when x = 3 and y = 4, what is dy/dt?

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14-03-2022

Answer:

dy/dt = -3/2

Step-by-step explanation:

x² + y² = 25

2x dx/dt + 2y dy/dt = 0

x dx/dt + y dy/dt = 0

3 * 2 + 4 dy/dt = 0

so

dy/dt = -6/4 = -3/2

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