Answer:
(x − 2)×(3x+1)
Step-by-step explanation:
We can use this method:
[tex]\begin{aligned}3 x^{2}-5 x-2 &=3 x^{2}-5 x-x+x-2 \\\\&=3 x^{2}-6 x+x-2 \\\\&=3 x \cdot(x-2)+(x-2) \\\\&=(x-2)(3 x+1)\end{aligned}[/tex]
All I did is Subtracting x then adding x which will not affect the result because -x + x = 0
