Hii there !
The reaction accompanying production of water in this case would be -
[tex]\green{ \underline { \boxed{ \sf{H_2+ \frac{1}{2}O_2\longrightarrow H_2O}}}}[/tex]
Thus ,by observing the reaction, we can conclude that 1 mole of Hydrogen (H[tex]_2[/tex])react with 1/2 mole of oxygen(O[tex]_2[/tex])to produce 1 mole of water (H[tex]_2[/tex]O)
[tex]\implies[/tex]Therefore, 37.0 moles of hydrogen(H[tex]_2[/tex]) will be required to produce 37.0 moles of water.
Hope it helps.
