Answer:
[tex]x = -\dfrac{48}5[/tex]
Step by step explanation:
[tex]~~~~~~~\dfrac{x^2+12x+36}{2x^2}-\dfrac{x^2 +7x +12}{2x^2}= \dfrac 5{4x}\\\\\\\implies \dfrac{x^2 +12x +36 -x^2 -7x -12}{2x^2 } = \dfrac 5{4x}\\\\\\\implies \dfrac{5x+24}{2x^2} = \dfrac 5{4x}\\\\\\\implies 4x(5x+24) = 5(2x^2)\\\\\\\implies 20x^2+96x= 10x^2\\\\\\\implies 20x^2 -10x^2 +96x=0\\\\\\\implies 10x^2 +96x= 0\\\\\\\implies 5x^2 +48x = 0\\\\\\\implies x(5x+48)=0\\\\\\\implies x = -\dfrac{48}5~~~~~;[x\neq 0][/tex]
