Respuesta :

apologiabiology
distribute
just like distributive porpetty but longer
remember
a(b+c)=ab+ac so
a(b+c+d)=ab+ac+ad

5w(-3w²+2w-4)=
5w(-3w²)+5w(2w)+5w(-4)=
(5)(w)(-3)(w²)+(5)(w)(2)(w)+(5)(w)(-4)=
(5)(-3)(w)(w²)+(5)(2)(w)(w)+(5)(-4)(w)=
-15w³+10w²-20w
-24w(to the 4th power)

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